The amplitude of a damped oscillator decreases to 0.9 times its original magnitude is 5s. In another 10s it will decrease to α times its original magnitude, where α equals.
Text Solution
Verified by ExpertsThe correct answer is:
C
A = A 0 
after 5 second
0.9A 0 = A 0
...(i)
After 10 more second
A = A 0
...(ii)
From (i) & (ii)
A = 0.729 A 0
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A mass M, attached to a horizontal spring, executes SHM with a amplitude A 1 . When the mass M pass…
Two particles are executing simple harmonic motion of the same amplitude A and frequency ꞷ along th…
If a simple pendulum has significant amplitude (up to a factor of 1/e of original) only in the peri…
A particle moves with simple harmonic motion in a straight line. In first τ s, after starting from …
For a simple pendulum, a graph is plotted between its kinetic energy (KE) and potential energy (PE)…
A particle performs simple harmonic motion with amplitude A. Its speed is trebled at the instant th…